Solve $b_{1} = 8 cm, b_{2} = 12 cm, h = 5 cm$

Step-by-step solution

Step 1 · Trapezoid area
$A = \frac{b _{1} + b _{2}}{2} h$
The bases are the parallel sides and the height is their perpendicular separation.
Step 2 · Substitute
$A = \frac{8 + 12}{2} \cdot 5 = 50 cm^{2}$
The mean base length is 10 cm. Multiplying two lengths gives square centimetres.

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